3x^2+23x-6.9=0

Solution for 3x^2+23x-6.9=0 equation:

3x^2+23x-6.9=0

a = 3; b = 23; c = -6.9;
Δ = b2-4ac
Δ = 232-4·3·(-6.9)
Δ = 611.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{611.8}}{2*3}=\frac{-23-\sqrt{611.8}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{611.8}}{2*3}=\frac{-23+\sqrt{611.8}}{6}
$